Integrand size = 22, antiderivative size = 70 \[ \int \frac {x^5}{\left (a+b x^2\right ) \left (c+d x^2\right )} \, dx=\frac {x^2}{2 b d}+\frac {a^2 \log \left (a+b x^2\right )}{2 b^2 (b c-a d)}-\frac {c^2 \log \left (c+d x^2\right )}{2 d^2 (b c-a d)} \]
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Time = 0.05 (sec) , antiderivative size = 70, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {457, 84} \[ \int \frac {x^5}{\left (a+b x^2\right ) \left (c+d x^2\right )} \, dx=\frac {a^2 \log \left (a+b x^2\right )}{2 b^2 (b c-a d)}-\frac {c^2 \log \left (c+d x^2\right )}{2 d^2 (b c-a d)}+\frac {x^2}{2 b d} \]
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Rule 84
Rule 457
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \text {Subst}\left (\int \frac {x^2}{(a+b x) (c+d x)} \, dx,x,x^2\right ) \\ & = \frac {1}{2} \text {Subst}\left (\int \left (\frac {1}{b d}+\frac {a^2}{b (b c-a d) (a+b x)}+\frac {c^2}{d (-b c+a d) (c+d x)}\right ) \, dx,x,x^2\right ) \\ & = \frac {x^2}{2 b d}+\frac {a^2 \log \left (a+b x^2\right )}{2 b^2 (b c-a d)}-\frac {c^2 \log \left (c+d x^2\right )}{2 d^2 (b c-a d)} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 66, normalized size of antiderivative = 0.94 \[ \int \frac {x^5}{\left (a+b x^2\right ) \left (c+d x^2\right )} \, dx=\frac {a^2 d^2 \log \left (a+b x^2\right )-b \left (d (-b c+a d) x^2+b c^2 \log \left (c+d x^2\right )\right )}{2 b^2 d^2 (b c-a d)} \]
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Time = 2.71 (sec) , antiderivative size = 65, normalized size of antiderivative = 0.93
method | result | size |
default | \(\frac {x^{2}}{2 b d}-\frac {a^{2} \ln \left (b \,x^{2}+a \right )}{2 \left (a d -b c \right ) b^{2}}+\frac {c^{2} \ln \left (d \,x^{2}+c \right )}{2 \left (a d -b c \right ) d^{2}}\) | \(65\) |
norman | \(\frac {x^{2}}{2 b d}-\frac {a^{2} \ln \left (b \,x^{2}+a \right )}{2 \left (a d -b c \right ) b^{2}}+\frac {c^{2} \ln \left (d \,x^{2}+c \right )}{2 \left (a d -b c \right ) d^{2}}\) | \(65\) |
risch | \(\frac {x^{2}}{2 b d}-\frac {a^{2} \ln \left (-b \,x^{2}-a \right )}{2 b^{2} \left (a d -b c \right )}+\frac {c^{2} \ln \left (d \,x^{2}+c \right )}{2 \left (a d -b c \right ) d^{2}}\) | \(68\) |
parallelrisch | \(-\frac {-x^{2} a b \,d^{2}+x^{2} b^{2} c d +\ln \left (b \,x^{2}+a \right ) a^{2} d^{2}-\ln \left (d \,x^{2}+c \right ) b^{2} c^{2}}{2 b^{2} d^{2} \left (a d -b c \right )}\) | \(70\) |
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Time = 0.25 (sec) , antiderivative size = 72, normalized size of antiderivative = 1.03 \[ \int \frac {x^5}{\left (a+b x^2\right ) \left (c+d x^2\right )} \, dx=\frac {a^{2} d^{2} \log \left (b x^{2} + a\right ) - b^{2} c^{2} \log \left (d x^{2} + c\right ) + {\left (b^{2} c d - a b d^{2}\right )} x^{2}}{2 \, {\left (b^{3} c d^{2} - a b^{2} d^{3}\right )}} \]
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Timed out. \[ \int \frac {x^5}{\left (a+b x^2\right ) \left (c+d x^2\right )} \, dx=\text {Timed out} \]
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Time = 0.20 (sec) , antiderivative size = 68, normalized size of antiderivative = 0.97 \[ \int \frac {x^5}{\left (a+b x^2\right ) \left (c+d x^2\right )} \, dx=\frac {a^{2} \log \left (b x^{2} + a\right )}{2 \, {\left (b^{3} c - a b^{2} d\right )}} - \frac {c^{2} \log \left (d x^{2} + c\right )}{2 \, {\left (b c d^{2} - a d^{3}\right )}} + \frac {x^{2}}{2 \, b d} \]
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Time = 0.29 (sec) , antiderivative size = 70, normalized size of antiderivative = 1.00 \[ \int \frac {x^5}{\left (a+b x^2\right ) \left (c+d x^2\right )} \, dx=\frac {a^{2} \log \left ({\left | b x^{2} + a \right |}\right )}{2 \, {\left (b^{3} c - a b^{2} d\right )}} - \frac {c^{2} \log \left ({\left | d x^{2} + c \right |}\right )}{2 \, {\left (b c d^{2} - a d^{3}\right )}} + \frac {x^{2}}{2 \, b d} \]
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Time = 5.38 (sec) , antiderivative size = 68, normalized size of antiderivative = 0.97 \[ \int \frac {x^5}{\left (a+b x^2\right ) \left (c+d x^2\right )} \, dx=\frac {a^2\,\ln \left (b\,x^2+a\right )}{2\,b^3\,c-2\,a\,b^2\,d}+\frac {c^2\,\ln \left (d\,x^2+c\right )}{2\,a\,d^3-2\,b\,c\,d^2}+\frac {x^2}{2\,b\,d} \]
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